2j(7j^2+jk^2+5k)-9k(-2j^2k^2+2k^2+3j)=0

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Solution for 2j(7j^2+jk^2+5k)-9k(-2j^2k^2+2k^2+3j)=0 equation: 


Simplifying
2j(7j2 + jk2 + 5k) + -9k(-2j2k2 + 2k2 + 3j) = 0

Reorder the terms:
2j(jk2 + 7j2 + 5k) + -9k(-2j2k2 + 2k2 + 3j) = 0
(jk2 * 2j + 7j2 * 2j + 5k * 2j) + -9k(-2j2k2 + 2k2 + 3j) = 0

Reorder the terms:
(10jk + 2j2k2 + 14j3) + -9k(-2j2k2 + 2k2 + 3j) = 0
(10jk + 2j2k2 + 14j3) + -9k(-2j2k2 + 2k2 + 3j) = 0

Reorder the terms:
10jk + 2j2k2 + 14j3 + -9k(3j + -2j2k2 + 2k2) = 0
10jk + 2j2k2 + 14j3 + (3j * -9k + -2j2k2 * -9k + 2k2 * -9k) = 0
10jk + 2j2k2 + 14j3 + (-27jk + 18j2k3 + -18k3) = 0

Reorder the terms:
10jk + -27jk + 2j2k2 + 18j2k3 + 14j3 + -18k3 = 0

Combine like terms: 10jk + -27jk = -17jk
-17jk + 2j2k2 + 18j2k3 + 14j3 + -18k3 = 0

Solving
-17jk + 2j2k2 + 18j2k3 + 14j3 + -18k3 = 0

Solving for variable 'j'.

The solution to this equation could not be determined.

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